[Jun-2026 Newly Released] CEM Dumps for Energy Management Certified
Updated Verified CEM dumps Q&As - 100% Pass
NEW QUESTION # 78
You can buy air compressor A for $15,000 or air compressor B for $6,000. Compressor A will cost $10,000 per year to operate. Compressor B will cost $11,500 per year to operate. If both air compressors have a 10- year life and your required return on investment is 12%, which air compressor has the lowest total life-cycle cost?
- A. Compressor B
- B. Both air compressors have the same life-cycle cost
- C. Compressor A
Answer: A
NEW QUESTION # 79
A concentrating solar thermal system collects 5 GJ/h of thermal heat, which is delivered to a 94% efficient hot water generator. The hot water generator is used to raise the water temperature from 15°C to 65°C. The specific heat of water (Cp) is 4.2 kJ/kg-°C. What flow rate (liter/second) of hot water can be delivered from the hot water generator?
- A. 9.2 liter/second
- B. 6.2 liter/second
- C. 4.2 liter/second
- D. 12.0 liter/second
Answer: A
Explanation:
Step 1: Compute Useful Thermal Energy Output
Given:
* Solar system delivers 5 GJ/h
* Hot water generator efficiency = 94%
NEW QUESTION # 80
A facility has the thermal cooling load profile shown in the table below. The utility rate traffic has an no-peak time-of-use period that begins at 10:00 a.m ends at 7:00 p.m. What chiller capacity (output) is required for a load-leveling operating strategy?
[Question from the previous image, which was about chiller capacity for load leveling, but the table was missing]
- A. 7.0 GJ/h
- B. 4.0 GJ/h
- C. 8.0 GJ/h
- D. 5.0 GJ/h
Answer: D
Explanation:
Comprehensive Detailed Step by Step Explanation with all AEE Energy Manager (CEM) References
* Interpret the load profile (hourly cooling energy):The table gives the facility cooling load in GJ per hour interval (so numerically it's an hourly rate for each hour).
* Compute the total daily cooling energy (sum of 24 hourly loads):
* 12:00 a.m.-6:00 a.m.: 6 hr × 2 = 12 GJ
* 6:00-7:00 a.m.: 4 # 16 GJ
* 7:00-8:00 a.m.: 4 # 20 GJ
* 8:00-9:00 a.m.: 4 # 24 GJ
* 9:00-10:00 a.m.: 6 # 30 GJ
* 10:00-11:00 a.m.: 6 # 36 GJ
* 11:00 a.m.-12:00 p.m.: 8 # 44 GJ
* 12:00-1:00 p.m.: 8 # 52 GJ
* 1:00-2:00 p.m.: 9 # 61 GJ
* 2:00-3:00 p.m.: 9 # 70 GJ
* 3:00-4:00 p.m.: 9 # 79 GJ
* 4:00-5:00 p.m.: 9 # 88 GJ
* 5:00-6:00 p.m.: 8 # 96 GJ
* 6:00-7:00 p.m.: 6 # 102 GJ
* 7:00-8:00 p.m.: 6 # 108 GJ
* 8:00-9:00 p.m.: 4 # 112 GJ
* 9:00-10:00 p.m.: 4 # 116 GJ
* 10:00-11:00 p.m.: 2 # 118 GJ
* 11:00 p.m.-12:00 a.m.: 2 # 120 GJ total per day
So, Total daily cooling energy = 120 GJ.
* Apply the CEM "load-leveling" operating strategy sizing rule:In the AEE CEM Thermal Storage training material, Load Leveling is described as operating the chiller at a constant (or near constant) load for 24 hours per day, and the "load leveling chiller load calculations" are based on Total energy
/ Hours available to operate chillers-for load leveling, that operating window is 24 hours. portal.
aeecenter.org
Therefore:
* Why the "no-peak 10 a.m.-7 p.m." detail doesn't change the load-leveling answer:That time window is typically used when a strategy restricts chiller operation to certain hours (e.g., full load shifting). But load leveling, per the CEM training description, is the strategy where the chiller runs all day at (near) constant load, using storage to absorb the difference between constant production and variable building load
NEW QUESTION # 81
You are using a performance contract to finance the added cost of using more-efficient equipment in the construction of a new building. Which of the following International Performance Measurement and Verification Protocol (IPMVP) options would you use to verify annual energy savings?
- A. Option C - Whole facility measurement
- B. Option A - Retrofit isolation: key parameter measurement
- C. Option E - Stipulated savings
- D. Option D - Calibrated simulation
- E. Option B - Retrofit isolation: all parameter measurement
Answer: A
NEW QUESTION # 82
When comparing two similar facilities, you see that the facility with newer, higher-efficiency equipment has a higher energy-use index [EUI] (kJ/m²-yr). What might be the cause?
- A. The facility with the lower EUI is in need of commissioning
- B. The facility with the higher EUI requires a supervisory control and data acquisition (SCADA) system
- C. The facility with the higher efficiency equipment should have a higher EUI
- D. The facility with the higher EUI is in need of commissioning
- E. The facility with the lower EUI requires a performance contract
Answer: D
Explanation:
1) CEM Principle: Equipment Efficiency # System Performance
The AEE CEM Body of Knowledge stresses that higher-efficiency equipment does not guarantee lower energy use unless systems are:
* Properly commissioned
* Correctly controlled
* Operated as designed
2) Evaluation of Options
* A. The facility with the higher EUI is in need of commissioning #
* Most common cause per CEM case studies: controls, sequences, and integration not optimized.
* B. The facility with the lower EUI is in need of commissioning #
* Lower EUI indicates better performance.
* C. The facility with the lower EUI requires a performance contract #
* No evidence supports this.
* D. The facility with the higher efficiency equipment should have a higher EUI #
* Contradicts energy efficiency principles.
* E. The facility with the higher EUI requires a SCADA system #
* Monitoring alone does not correct poor performance.
CEM Exam Insight
Commissioning ensures that high-efficiency equipment actually delivers expected energy performance.
NEW QUESTION # 83
Using a degree-day base of 18°C, calculate the number of cooling degree days (CDD) if the outside temperature is a uniform 25°C throughout the year (365 days/year).
- A. 1,845 CDD/yr
- B. 1,955 CDD/yr
- C. 2,975 CDD/yr
- D. 2,555 CDD/yr
- E. 2,250 CDD/yr
Answer: C
NEW QUESTION # 84
How does an enthalpy-based economizer control operate?
- A. Measuring the outdoor air dry-bulb temperature and relative humidity
- B. Using a constant mixed air proportion control sequence
- C. Comparing the difference in dry-bulb air temperature measurements of the return air and the outdoor air
- D. Using the dry-bulb temperature and relative humidity of both the outdoor-air and return-air
Answer: D
NEW QUESTION # 85
What is the main cause of low power factor?
- A. Fluorescent lighting
- B. Low-load induction motors
- C. Solar flares
- D. Computers and electronic equipment
- E. Harmonics
Answer: B
NEW QUESTION # 86
What will commonly be the most appropriate expected lamp life for a fluorescent lamp fitted with an occupancy sensor, that is operational in a school?
SELECT THE CORRECT ANSWER
- A. 18,000 operational hours
- B. 1,000 operational hours
- C. 20,000 calendar hours
- D. 50,000 operational hours
- E. 50,000 calendar hours
Answer: A
NEW QUESTION # 87
Using the lumen method, calculate the number of luminaires (fixtures) required to light a room to 200 lux.
Each luminaire has 2 fluorescent lamps, 3,000 lumens per lamp. The room is 20 meters by 30 meters. The total light loss factor (LLF) is 0.70 and the luminaire coefficient of utilization (CU) is 0.80.
- A. 36 luminaires
- B. 24 luminaires
- C. 12 luminaires
- D. 60 luminaires
- E. 48 luminaires
Answer: A
NEW QUESTION # 88
A 25-kW motor, at full load, drives a centrifugal fan that produces 160,000 liters per second (l/s) of ventilation air. If the fan speed is reduced to a flow rate of 150,000 l/s, what is the new load on the motor?
- A. 20.6 kW
- B. 25.0 kW
- C. 15.2 kW
- D. 24.2 kW
- E. 30.3 kW
Answer: A
NEW QUESTION # 89
A 3 MW rated wind-powered turbine has a rotor diameter of 113 meters. What is the efficiency of the wind turbine at rated power if it is operating in wind power calculated at 8.6 MW? Assume an air density of 1.225 kg/m³.
- A. 42.7%
- B. 34.9%
- C. 28.4%
- D. 59.3%
Answer: B
NEW QUESTION # 90
Using the natural gas combustion efficiency tables in your workbook, find the combustion efficiency (based on higher-heating value) of a natural-gas-fired boiler if the excess air level is measured at 31.9% and the stack temperature rise is 187.8°C.
- A. 82%
- B. 80%
- C. 84%
- D. 76%
- E. 78%
Answer: A
NEW QUESTION # 91
What is the Energy Use index (EUl) for a 4,000 m2 building that uses the following amountsof energy each year?
- A. 1,612,000 kJ/m²-yr
- B. 855,250 kJ/m²-yr
- C. 403,311 kJ/m²-yr
- D. 3,220,800 kg/m²-yr
- E. 625,600 kJ/m²-yr
Answer: E
Explanation:
A screenshot of a math problem AI-generated content may be incorrect.
NEW QUESTION # 92
Which of the following statements regarding refrigerants is NOT correct?
5ELECT THE CORRECT ANSWER
- A. R-11 and R-12 are Chloro Fluoro Carbons with significant ozone depleting potential
- B. R-32 and R-134a are Hydro Fluoro Carbons with zero ozone depleting potential, and significant global warming impact
- C. R-1234yf is a Hydro Fluoro Olefin with zero ozone depleting potential, and little global warming potential
- D. R-407C is a blended Hydro Fluoro Carbon or near Azeotropic mixture, and can be used as a replacement for R-22 in commercial applications
- E. R-22 is a Hydro Chloro Carbon with significant ozone depleting potential and significant global warming impact
Answer: E
Explanation:
Understanding the environmental impacts of various refrigerants is crucial for energy managers. Let's analyze each statement:en.wikipedia.org A:R-407C is a blended Hydro Fluoro Carbon or near Azeotropic mixture, and can be used as a replacement for R-22 in commercial applications:This statement is correct. R-407C is a blend of HFCs designed to replace R-22 in air conditioning systems.
B:R-11 and R-12 are Chloro Fluoro Carbons with significant ozone depleting potential:This is correct. R-
11 and R-12 are CFCs known for their high ozone depletion potential.
C:R-1234yf is a Hydro Fluoro Olefin with zero ozone depleting potential, and little global warming potential:Correct. R-1234yf is an HFO with negligible ozone depletion and low global warming potential.
D:R-22 is a Hydro Chloro Carbon with significant ozone depleting potential and significant global warming impact:This statement is incorrect.R-22 is a Hydrochlorofluorocarbon (HCFC), not a Hydro Chloro Carbon.While it does have ozone-depleting potential, its global warming potential is considered moderate, not significant.
E:R-32 and R-134a are Hydro Fluoro Carbons with zero ozone depleting potential, and significant global warming impact:This is correct. Both R-32 and R-134a are HFCs with no ozone depletion potential but have considerable global warming potential.
Conclusion:
The incorrect statement is D. R-22 is a Hydro Chloro Carbon with significant ozone depleting potential and significant global warming impact. Therefore, the correct answer is D.
NEW QUESTION # 93
Which of the following is NOT included in commissioning documentation?
- A. Equipment control sequence documentation
- B. As-built drawings
- C. Financing payment structure reports
- D. Original facility and equipment design intent
- E. Equipment operations and maintenance manuals
Answer: C
NEW QUESTION # 94
If a boiler cycles on and off too frequently, what control can you adjust to reduce the number of times a boiler cycles on and off?
- A. Increase the controller differential
- B. Increase the controller set point
- C. Reduce the controller differential
Answer: C
NEW QUESTION # 95
What is the definition of lamp life for a fluorescent lamp?
- A. The time at which 50% of a large sample of lamps have failed
- B. The time at which lamps begin to fail
- C. The time at which lumen output has reduced to 70% of the initial light output
- D. The time at which 70% of a large sample of lamps have failed
- E. The time at which lumen output has reduced by 50%
Answer: C
NEW QUESTION # 96
When should commissioning be included in the design and construction of a facility?
- A. When the occupancy permit is accepted
- B. When the design is finalized
- C. When construction is finalized
- D. When the planning process begins
- E. When installation of the energy systems begins
Answer: D
NEW QUESTION # 97
A concentrating solar thermal system collects 5 GJ/h of thermal heat, which is delivered to a 94% efficient hot water generator. The hot water generator is used to raise the water temperature from 15°C to 65°C. The specific heat of water (Cp) is 4.2 kJ/kg-°C. What flow rate (liter/second) of hot water can be delivered from the hot water generator?
- A. 9.2 liter/second
- B. 6.2 liter/second
- C. 4.2 liter/second
- D. 12.0 liter/second
Answer: A
Explanation:
Step 1: Compute Useful Thermal Energy Output
Given:
* Solar system delivers5 GJ/h
* Hot water generator efficiency= 94%
A screenshot of a math problem AI-generated content may be incorrect.
NEW QUESTION # 98
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